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secondary 3 | A Maths
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Date Posted: 5 years ago
Views: 385
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i hope it helps !
Date Posted:
5 years ago
i dont mderstand how you derive to that suddenly
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since the cubic polynomial is a multiplication of a quadratic formula(given in question) and a linear formula(cx+constant number) , the unknown c is my linear formula's x coefficient(the number in front) .
so i know that the constant in the cubic formula is +14 and the constant in the quadratic formula is -7 , -7*-2 gives you +14, so you know the constant in your linear equation (cx-2) .
when you multiply and expand the linear and quadratic formula on the right hand side(i did not show in the working previously), you group the coefficients of x^3,x^2 and x respectively . after which , you compare the right hand side with your left hand side according to coefficient of x^3, x^2 and x separately .
hope it clarifies your doubt .
so i know that the constant in the cubic formula is +14 and the constant in the quadratic formula is -7 , -7*-2 gives you +14, so you know the constant in your linear equation (cx-2) .
when you multiply and expand the linear and quadratic formula on the right hand side(i did not show in the working previously), you group the coefficients of x^3,x^2 and x respectively . after which , you compare the right hand side with your left hand side according to coefficient of x^3, x^2 and x separately .
hope it clarifies your doubt .
Date Posted:
5 years ago
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