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Pls help me with question 3 and 4, they are challenging questions!!! Thank you very much
Date Posted: 6 years ago
Views: 387
3a) is correct .
Eg. 1 050 000 rounded to 1 100 000
3b)
To get the biggest percentage error possible, we have to divide the largest error of approximation , by the smallest possible 7 digit number that gives this error of approximation.
Assuming the maximum error of approximation (50000) is gives a percentage error of 5%,
the number = 5/100 x 50000
= 1 000 000
But, the smallest possible number that when rounded to 2 significant figures gives a maximum error of approximation of 50000 , is 1 050 000.
Since 1 050 000 > 1 000 000,
The percentage error of approximation can only be smaller than 5% since
50000/1 050 000 is smaller than 50000/1 000 000
Eg. 1 050 000 rounded to 1 100 000
3b)
To get the biggest percentage error possible, we have to divide the largest error of approximation , by the smallest possible 7 digit number that gives this error of approximation.
Assuming the maximum error of approximation (50000) is gives a percentage error of 5%,
the number = 5/100 x 50000
= 1 000 000
But, the smallest possible number that when rounded to 2 significant figures gives a maximum error of approximation of 50000 , is 1 050 000.
Since 1 050 000 > 1 000 000,
The percentage error of approximation can only be smaller than 5% since
50000/1 050 000 is smaller than 50000/1 000 000
You should post the full question for question 4. Only the description and the diagram is visible.
Ow I’m so sorry, will update later
Tysm
Tysm
I posted it as an answer, take a look
See 1 Answer
done
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The upper part:) thx
Date Posted:
6 years ago
Total time taken = 5 s
Total distance AB ≈ 8.225 cm (82.25mm)
So ∫(5,0) u dt = 82.25 mm
remember that the integral of speed/velocity is distance.
And u = Vo + at , where Vo is initial speed and a is acceleration
Refer to these slides :
https://www.google.com.sg/url?sa=i&source=images&cd=&ved=2ahUKEwji55DWor3dAhUEN48KHfjvCJkQjhx6BAgBEAM&url=https%3A%2F%2Fwww.google.com.sg%2Famp%2Fs%2Fslideplayer.com%2Famp%2F5225179%2F%3Fsource%3Dimages&psig=AOvVaw2sg6aCc8HrkRZgWM6hXUxw&ust=1537109322843891
Total distance AB ≈ 8.225 cm (82.25mm)
So ∫(5,0) u dt = 82.25 mm
remember that the integral of speed/velocity is distance.
And u = Vo + at , where Vo is initial speed and a is acceleration
Refer to these slides :
https://www.google.com.sg/url?sa=i&source=images&cd=&ved=2ahUKEwji55DWor3dAhUEN48KHfjvCJkQjhx6BAgBEAM&url=https%3A%2F%2Fwww.google.com.sg%2Famp%2Fs%2Fslideplayer.com%2Famp%2F5225179%2F%3Fsource%3Dimages&psig=AOvVaw2sg6aCc8HrkRZgWM6hXUxw&ust=1537109322843891
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