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a = 26, d = -2
Sn = n/2[2(26) + (n-1)(-2)] = 0
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=> n² - 27n = 0
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=> n = 0 (n.a.) or n = 27
ans: n = 27
Sn = n/2[2(26) + (n-1)(-2)] = 0
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=> n² - 27n = 0
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=> n = 0 (n.a.) or n = 27
ans: n = 27
Date Posted:
6 years ago
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hope it helps! feel free to ask if I were unclear
Date Posted:
6 years ago