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Question
primary 6 | Maths
| Measurement
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Pls help;TY
Date Posted: 6 years ago
Views: 426
smallest difference occurs at:
largest 2-digit no. &
smallest 3-digit no.
The largest possible 2-digit no. is 99.
hence, the 3-digit no. is 316 (=415-99)
thus, the smallest possible difference
= 316-99
= 217
largest 2-digit no. &
smallest 3-digit no.
The largest possible 2-digit no. is 99.
hence, the 3-digit no. is 316 (=415-99)
thus, the smallest possible difference
= 316-99
= 217
Thanks
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