Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
|
2 Answers Below
Anyone can contribute an answer, even non-tutors.
i need help with qsn 12
Date Posted: 5 years ago
Views: 245
(a)
BD² = 5² + 6² -2(5)(6)cos107°
(b)
BD² = 8² + 7² -2(8)(7)cos∠BCD
(c)
area of △ABD = ½(5)(6)sin107°
area of △BCD = ½(8)(7)sin∠BCD
area of ABCD
= area of △ABD + area of △BCD
BD² = 5² + 6² -2(5)(6)cos107°
(b)
BD² = 8² + 7² -2(8)(7)cos∠BCD
(c)
area of △ABD = ½(5)(6)sin107°
area of △BCD = ½(8)(7)sin∠BCD
area of ABCD
= area of △ABD + area of △BCD
See 2 Answers
360 Tutoring Program