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secondary 3 | E Maths
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Date Posted: 6 years ago
Views: 672
Assuming their speed were constant in that 3 hours,
Distance apart after 1 hour
= 444 km ÷ 3
= 148 km
This also means that in 1 hour, their combined travelled distance = 148 km
So one car is slower than the other car by 12 km/h. This means that in 1 hour, this car travels 12 km less that the faster car.
So 148 km - 12 km = 136 km
136 km ÷ 2 = 68 km
So the speed of the slower car is 68 km/h
Distance apart after 1 hour
= 444 km ÷ 3
= 148 km
This also means that in 1 hour, their combined travelled distance = 148 km
So one car is slower than the other car by 12 km/h. This means that in 1 hour, this car travels 12 km less that the faster car.
So 148 km - 12 km = 136 km
136 km ÷ 2 = 68 km
So the speed of the slower car is 68 km/h
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