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primary 6 | Maths
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Plz help ASAP, Tysm!
Date Posted: 6 years ago
Views: 1250
Firstly, find the angle sum of the 5 triangles.
5 x 180° = 900°
Then, see those unlabelled angles in each of the triangles? Their opposite angles are the same.
(There are 5 straight lines. And you know that opposite angles of any two straight lines are equal to each other)
These unlabelled angles all add up to 180°.
(Take line PMQ as a reference.)
So the answer is just 900° - all those unlabelled angles
= 900° - 180°
= 720°
5 x 180° = 900°
Then, see those unlabelled angles in each of the triangles? Their opposite angles are the same.
(There are 5 straight lines. And you know that opposite angles of any two straight lines are equal to each other)
These unlabelled angles all add up to 180°.
(Take line PMQ as a reference.)
So the answer is just 900° - all those unlabelled angles
= 900° - 180°
= 720°
Thx, I understand now
See 1 Answer
done
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Refer to my comment. Realise that
∠1 + ∠ 2 + ∠ 3 + ∠ 4 + ∠ 5 = 180°
∠1 + ∠ 2 + ∠ 3 + ∠ 4 + ∠ 5 = 180°
Date Posted:
6 years ago
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