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secondary 2 | Maths
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hello tutors. i need helo with 2 parts of this qn. i hope u can help me asap. thank you :))
Date Posted: 5 years ago
Views: 209
30.
(a)
1 + 1/(x-k) = (x-k+1)/(x-k)
(b)
(x-4)/(x-5)-(x-7)/(x-8) = (x-5)/(x-6)-(x-8)/(x-9)
=>1+1/(x-5)-[1+1/(x-8)] = 1+1/(x-6)-[1+1/(x-9)]
=>1/(x-5)-1/(x-8) = 1/(x-6)-1/(x-9)
.
.
.
=>(x-5)(x-8) = (x-6)(x-9)
.
.
.
=>x = 7
(a)
1 + 1/(x-k) = (x-k+1)/(x-k)
(b)
(x-4)/(x-5)-(x-7)/(x-8) = (x-5)/(x-6)-(x-8)/(x-9)
=>1+1/(x-5)-[1+1/(x-8)] = 1+1/(x-6)-[1+1/(x-9)]
=>1/(x-5)-1/(x-8) = 1/(x-6)-1/(x-9)
.
.
.
=>(x-5)(x-8) = (x-6)(x-9)
.
.
.
=>x = 7
See 1 Answer
done
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answered by this person. thank you for helping
Date Posted:
5 years ago
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