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Primary 4 | Maths
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Date Posted: 5 years ago
Views: 253
Let number of boys at first be 4 units.
¼ of the boys left → 4 units - 1 unit
= 3 units remaining
Number of girls remaining = number of boys remaining = 3 units
125 - 20 = 105 = number of girls remaining + total number of boys at first
= 3 units + 4 units
= 7 units
1 unit = 105 ÷ 7 = 15
Number of girls at first
= 3 units + 20
= 3 x 15 + 20
= 45 + 20
= 65
Alternatively, number of girls at first
= Total number of girls and boys at first - number of boys at first
= 125 - 4 units
= 125 - 4 x 15
= 125 - 60
= 65
¼ of the boys left → 4 units - 1 unit
= 3 units remaining
Number of girls remaining = number of boys remaining = 3 units
125 - 20 = 105 = number of girls remaining + total number of boys at first
= 3 units + 4 units
= 7 units
1 unit = 105 ÷ 7 = 15
Number of girls at first
= 3 units + 20
= 3 x 15 + 20
= 45 + 20
= 65
Alternatively, number of girls at first
= Total number of girls and boys at first - number of boys at first
= 125 - 4 units
= 125 - 4 x 15
= 125 - 60
= 65
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Date Posted:
5 years ago
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