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## Question

primary 6 | Maths
| Geometry

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Working

Area of triangle ADC = 1/2 X 8cm (AB = DC) X 12cm (AD = BC) = 48cm2

Area of Rectangle ACYZ = 48cm2 X 2 = 96cm2

ACYZ.

ADC = 48 cm² (refer to above comment).

Notice that the vertical height of ADC is the same as the breadth of ACYZ. And it's base is just the length of ACYZ. So that's why it's ½ of ACYZ.

Area of ADC = ½ x vertical height x base

Area of ADC = ½ x breadth of ACYZ x length of ACYZ

48 cm² = ½ x breadth of ACYZ x 15 cm

Breadth of ACYZ

= 48 cm² ÷ ½ ÷ 15 cm

= 6.4 cm

ACYZ,

area of ACYZ = 48 x 2 = 96 cm²

Breadth of ACYZ = area ÷ length

= 96 cm² ÷ 15 cm

= 6.4 cm

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