Ask Singapore Homework?

Upload a photo of a Singapore homework and someone will email you the solution for free.



Question

primary 6 | Maths | Geometry
One Answer Below

Anyone can contribute an answer, even non-tutors.

Answer This Question
Matthew wan
Matthew Wan

primary 6 chevron_right Maths chevron_right Geometry

Working

Date Posted: 1 year ago
Views: 66
Crystal Tham
Crystal Tham
1 year ago
Triangle ADC is half of Rectangle ACYZ.

Area of triangle ADC = 1/2 X 8cm (AB = DC) X 12cm (AD = BC) = 48cm2

Area of Rectangle ACYZ = 48cm2 X 2 = 96cm2
J
J
1 year ago
The question is asking for the breadth of
ACYZ.

ADC = 48 cm² (refer to above comment).

Notice that the vertical height of ADC is the same as the breadth of ACYZ. And it's base is just the length of ACYZ. So that's why it's ½ of ACYZ.


Area of ADC = ½ x vertical height x base
Area of ADC = ½ x breadth of ACYZ x length of ACYZ

48 cm² = ½ x breadth of ACYZ x 15 cm

Breadth of ACYZ

= 48 cm² ÷ ½ ÷ 15 cm

= 6.4 cm
J
J
1 year ago
Alternatively, knowing that ADC is half of
ACYZ,

area of ACYZ = 48 x 2 = 96 cm²

Breadth of ACYZ = area ÷ length

= 96 cm² ÷ 15 cm
= 6.4 cm

See 1 Answer

done {{ upvoteCount }} Upvotes
clear {{ downvoteCount * -1 }} Downvotes
KingKong
Kingkong's answer
28 answers (A Helpful Person)
1st
Ans: 6.4cm