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Question
primary 6 | Maths
| Geometry
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Working
Area of triangle ADC = 1/2 X 8cm (AB = DC) X 12cm (AD = BC) = 48cm2
Area of Rectangle ACYZ = 48cm2 X 2 = 96cm2
ACYZ.
ADC = 48 cm² (refer to above comment).
Notice that the vertical height of ADC is the same as the breadth of ACYZ. And it's base is just the length of ACYZ. So that's why it's ½ of ACYZ.
Area of ADC = ½ x vertical height x base
Area of ADC = ½ x breadth of ACYZ x length of ACYZ
48 cm² = ½ x breadth of ACYZ x 15 cm
Breadth of ACYZ
= 48 cm² ÷ ½ ÷ 15 cm
= 6.4 cm
ACYZ,
area of ACYZ = 48 x 2 = 96 cm²
Breadth of ACYZ = area ÷ length
= 96 cm² ÷ 15 cm
= 6.4 cm
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