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## Question

primary 6 | Maths
| Geometry

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Please kindly and clearly explain to me how do I get the answer for this question. Thanks :)

Base of the shaded triangle

= 2 x width of a rectangle

= 2 units

Height of shaded triangle is the same as the length of the rectangles.

Area of shaded triangle

= ½ x base x height of shaded triangle

= ½ x 2 units x height of shaded triangle

= 1 unit x height of shaded triangle

Area of the whole figure (the big rectangle)

= width x length

= 4 units x length

= 4 units x height of shaded triangle

From above, you can see that the shaded triangle is ¼ of the whole figure

You should be able to see one unshaded rectangle and two unshaded triangles.

One of the unshaded triangles is ½ of 3 rectangles.

So its area = ½ x area of 3 rectangles

= area of 1½ rectangles.

The other shaded triangle is half of 1 rectangle.

So its area = ½ x area of 1 rectangle

= area of ½ rectangle.

Total unshaded area

= Area of 1½ rectangles + area of 1 rectangle + area of ½ rectangle

= Area of 3 rectangles

Area of whole figure = area of 4 rectangles

So, unshaded area = area of 4 rectangles

- area of 3 rectangles

= area of 1 rectangle

So you get the same result, ¼ of the figure is shaded.

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