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primary 6 | Maths
| Ratio
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Plz help ASAP, thanks!
Date Posted: 6 years ago
Views: 614
Find area of ∆ VSR first.
Then find area of ∆ TSR. (Hint: lines PR and each QS divide the rectangle into two equal parts)
Area of ∆ VSR - area of ∆ TSR
= area of ∆ VSU + area of ∆ TUR
Area of ∆PTQ - area of TUVW
= area of ∆ PWV + area of ∆ VUQ
(Hint: ∆ PTQ's area is the same as ∆ TSR's area)
Now you would have all the unshaded areas. So use it to find the shaded area and then you can find the ratio.
Then find area of ∆ TSR. (Hint: lines PR and each QS divide the rectangle into two equal parts)
Area of ∆ VSR - area of ∆ TSR
= area of ∆ VSU + area of ∆ TUR
Area of ∆PTQ - area of TUVW
= area of ∆ PWV + area of ∆ VUQ
(Hint: ∆ PTQ's area is the same as ∆ TSR's area)
Now you would have all the unshaded areas. So use it to find the shaded area and then you can find the ratio.
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