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primary 5 | Maths
| Area & Volume
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Date Posted: 5 years ago
Views: 431
Triangle BGD is common to both. So ABGH is 11cm² smaller than GFED.
GF = BF - BG = 11 cm - 4 cm = 7 cm
Area ABGH + 11 cm² = Area GFED
AH x GH + 11 cm² = GF x ED
4 cm x GH + 11 cm² = 7 cm x (11 cm - GH)
4 cm x GH + 11 cm² = 77 cm² - 7cm x GH
11 cm x GH = 66 cm²
GH = 66 cm² ÷ 6 = 6 cm
ED = 11 cm - GH = 11 cm - 6 cm = 5 cm
GF = BF - BG = 11 cm - 4 cm = 7 cm
Area ABGH + 11 cm² = Area GFED
AH x GH + 11 cm² = GF x ED
4 cm x GH + 11 cm² = 7 cm x (11 cm - GH)
4 cm x GH + 11 cm² = 77 cm² - 7cm x GH
11 cm x GH = 66 cm²
GH = 66 cm² ÷ 6 = 6 cm
ED = 11 cm - GH = 11 cm - 6 cm = 5 cm
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Solved with algaebra. Hope this help you.
Date Posted:
5 years ago
Thank you
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