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secondary 2 | Maths
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Gradient of a straight line
Date Posted: 6 years ago
Views: 294
gradient m = (y-8)/(x-0) = ⁴⁄₃
eqn of line:
y-8 = ⁴⁄₃x
=> y = ⁴⁄₃x + 8
B is x-intercept.
y of B is 0.
hence,
0 = ⁴⁄₃x + 8
x = -6
hence, B(-6, 0)
eqn of line:
y-8 = ⁴⁄₃x
=> y = ⁴⁄₃x + 8
B is x-intercept.
y of B is 0.
hence,
0 = ⁴⁄₃x + 8
x = -6
hence, B(-6, 0)
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Date Posted:
6 years ago
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