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Let the amount Solomon spent be $x.
Hence Diyana spent $3x. (Spent 3 times as much as Solomon)
Diyana also spent $48 more than Solomon.
Hence 3x - x = 2x = $48, x = $24.
Solomon spent $24
Diyana spent 24 +48 =$72 (where she is then left with half)
So, original Diyana amount = $72 x 2 = $144.
Since Solomon brought $126 more than Diyana, Solomon brought $144 + $126 = $270
Solomon spent $24, hence he has
$270 - $24 = $246 left.
Hence Diyana spent $3x. (Spent 3 times as much as Solomon)
Diyana also spent $48 more than Solomon.
Hence 3x - x = 2x = $48, x = $24.
Solomon spent $24
Diyana spent 24 +48 =$72 (where she is then left with half)
So, original Diyana amount = $72 x 2 = $144.
Since Solomon brought $126 more than Diyana, Solomon brought $144 + $126 = $270
Solomon spent $24, hence he has
$270 - $24 = $246 left.
Date Posted:
6 years ago
Thanks for the kind explanation. Appreciate it.
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See prev answer
Date Posted:
6 years ago