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Question
secondary 4 | A Maths
3 Answers Below
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please help! thank u
Date Posted: 6 years ago
Views: 444
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what is the first equation?
Sub (0,0)
So y=0, x=0
The first eqn: d=0
So y=0, x=0
The first eqn: d=0
but how does that help to solve a,b and c? my 2nd equation is 12a+4b+c=0 and 3rd equation is 8a+4b+2c=-4
done
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Okay, this time confirm plus chop correct, I checked with calculator, ahh paiseh paiseh
Date Posted:
6 years ago
done
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Ahh okay, sorry I realised I missed out another clue
Date Posted:
6 years ago
how do u know it is a(x-2)^2-4 instead of a (x+2)^2-4?
sorry, pls ignore^ however I cannot solve (I subbed 3 and 4 into one of the equation but there's no 'a' left
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