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primary 6 | Maths
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Date Posted: 6 years ago
Views: 332
Ties Wallets
4n 1n
Cost(c) c+$50
t+$184 Total cost of wallet (t) $840
$512 $328
t + $184 + t=$840
2t = 656
t = $328
4nc = 512
c = 512/4n
1n(c+50) = 328
1n(512/4n +50) =328
512/4 +50n = 328
128 +50n =328
n = 4
He bought 4 wallets.
Check:
Each wallet cost c+50 =512/4n +50 = $82
Total cost = 82*4 =$328
Each tie cost $32
Total cost = 32*4*n = 32*4*4 = $512
4n 1n
Cost(c) c+$50
t+$184 Total cost of wallet (t) $840
$512 $328
t + $184 + t=$840
2t = 656
t = $328
4nc = 512
c = 512/4n
1n(c+50) = 328
1n(512/4n +50) =328
512/4 +50n = 328
128 +50n =328
n = 4
He bought 4 wallets.
Check:
Each wallet cost c+50 =512/4n +50 = $82
Total cost = 82*4 =$328
Each tie cost $32
Total cost = 32*4*n = 32*4*4 = $512
See 1 Answer
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Draw model
Make a supposition
Make a supposition
Date Posted:
6 years ago
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