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Secondary 1 | Maths
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Date Posted: 6 years ago
Views: 473
Use prime factorisation.
594 ÷ 2 = 297
297 ÷ 3 = 99
99 ÷ 3 = 33
33 ÷ 3 = 11
11 is a prime number
So 594 = 2 x 3 x 3 x 3 x 11
Since each side has more than 3 cubes,
Smallest side has to be 2 x 3 = 6
You have two 3s and one 11 left. Only way to have the two other sides to have more than 3 cubes is :
3 x 3 = 9
11
So 594 = 6 x 9 x 11.
Longest side is 11 cubes.
594 ÷ 2 = 297
297 ÷ 3 = 99
99 ÷ 3 = 33
33 ÷ 3 = 11
11 is a prime number
So 594 = 2 x 3 x 3 x 3 x 11
Since each side has more than 3 cubes,
Smallest side has to be 2 x 3 = 6
You have two 3s and one 11 left. Only way to have the two other sides to have more than 3 cubes is :
3 x 3 = 9
11
So 594 = 6 x 9 x 11.
Longest side is 11 cubes.
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