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secondary 4 | A Maths
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Need help with part (ii)
Date Posted: 6 years ago
Views: 310
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As seen from the graph, as t get larger, the value for e^(-2t) gets close to 0.
Thus, the highest value for v can be assumed to be
V = 5 - (0)
= 5
Thus, the highest value for v can be assumed to be
V = 5 - (0)
= 5
Date Posted:
6 years ago
Wrong picture :(
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iia) Speed is greatest when you stop accelerating.
iib) distance is greatest when acceleration is 0 as thats where you travelled furthest in the direction before acceleration become either a negative number or positive number
iib) distance is greatest when acceleration is 0 as thats where you travelled furthest in the direction before acceleration become either a negative number or positive number
Date Posted:
6 years ago
Wrong. Displacement hits a stationary point when velocity is zero, not acceleration.
Whoops :(
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continued on page 2
Date Posted:
6 years ago
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page 2. i have explained different ways. feel free to question if you have further queries.
Date Posted:
6 years ago
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