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Question
secondary 4 | A Maths
2 Answers Below
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Date Posted: 6 years ago
Views: 345
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Tangent inverse the last part and reject the one out of range :P
Date Posted:
6 years ago
sorry but the correct answer is -1/3, i just could not get the working to get there
Oops i made a mistake haha give me awhile
sorry there many be typo, (tan2a+b) should be (tan(2a+b)), i will check to cfm
yeah it is a typo
Yeah haha if not i get 4tan^2b +BtanB - 1 cant solve
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Sub the tan2A = 4tanB in
Date Posted:
6 years ago
in 2nd quadrant, tangent is -ve, so only -1/3 is the answer
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