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junior college 1 | H1 Maths
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Newzealand
Newzealand

junior college 1 chevron_right H1 Maths

Can anyone help me to solve that 2 questions??

Date Posted: 6 years ago
Views: 384

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Jiayang
Jiayang's answer
1883 answers (Tutor Details)
1st
Newzealand
Newzealand
6 years ago
Thank you very much for helping me
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Eugene Chow
Eugene Chow's answer
3 answers (Tutor Details)
Look up the power rules and it will help a lot.
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Tay Cong Run
Tay Cong Run's answer
6 answers (Tutor Details)
1) ln(e) = 1. The strategy is to manipulate both sides to be in the form of ln ( ) = ln ( ) so you can get rid of the ln. After which, make y the subject. e is a constant whose value you can find using the calculator. So once you have y expressed in terms of e, you have the answer.

2) Since 3, 5 and 8 have no common prime factors, this question cannot be tackled using prime factorisation. Since the unknown is in the power, your intuition should be to bring the power down (using logarithms). Unless otherwise specified by the question, the simplest is to use the natural logarithm, ln, so as to avoid having to change bases. Of course, you can work with log base 3, 5 and 8, but it will be cumbersome to key into your calculator. Once you bring the power down, simply make x the subject. It is important to note that ln 8 - ln 3 - ln 5 is negative, so dividing by it means the direction of the equality sign must be reversed.