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primary 6 | Maths
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Date Posted: 6 years ago
Views: 253
Hi by any chance that you are looking for a cheap math tutor? I'm a jc student doing part time tutoring :D
Hi! For Qns 30:
1. Find out angle CDB
CDB=180-CDE
CDB=180-110=70
2. Remember that ABCD is a rhombus, so line CD= line CB, hence triangle CDB is an isosceles triangle. Finding out angle BCD will help you get the answer for angle BAD, as opposite angles in rhombus are equal.
BCD=180-CDB-CBD
BCD=180-70-70
BCD=BAD=40.
Hope that helps.
1. Find out angle CDB
CDB=180-CDE
CDB=180-110=70
2. Remember that ABCD is a rhombus, so line CD= line CB, hence triangle CDB is an isosceles triangle. Finding out angle BCD will help you get the answer for angle BAD, as opposite angles in rhombus are equal.
BCD=180-CDB-CBD
BCD=180-70-70
BCD=BAD=40.
Hope that helps.
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Here’s question 29! Hopefully it helps (:
Date Posted:
6 years ago
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