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secondary 3 | A Maths
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need help with example 3,, i don't understand the question?
Date Posted: 8 years ago
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a) From the graph you can see that when x is equal to or greater than -2 and equal to or lesser than 3, the corresponding values of y is greater or equal to 0 and lesser than or equal to 5.
b) The answer is wrong since abs(x^2-2x-3) will be greater than or equal to x-3 for every value of x. The answer is x is lesser than or equal to 0 or greater than or equal to 3 because it uses (x^2-2x-3) as the quadratic equation and not the modulus version as stated in the question.
b) The answer is wrong since abs(x^2-2x-3) will be greater than or equal to x-3 for every value of x. The answer is x is lesser than or equal to 0 or greater than or equal to 3 because it uses (x^2-2x-3) as the quadratic equation and not the modulus version as stated in the question.
Date Posted:
8 years ago
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This is the graph that example 3b used. Should probably clarify with your teacher.
:)
:)
Date Posted:
8 years ago
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