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The key to solving this question is to realise that the total number of stickers doesn't change.
Both the models shown above are "after" models, because the before is not important.
First model shows that after receiving 10 stickers from J, S would have 1/4 the number of stickers.
Second model shows that after receiving 34 stickers from J, S would have 1/2 the number of stickers.
5S + 50 = 3S + 102
2S = 52
S = 26
This is the least algebraic method I can come up with.
Both the models shown above are "after" models, because the before is not important.
First model shows that after receiving 10 stickers from J, S would have 1/4 the number of stickers.
Second model shows that after receiving 34 stickers from J, S would have 1/2 the number of stickers.
5S + 50 = 3S + 102
2S = 52
S = 26
This is the least algebraic method I can come up with.
Date Posted:
7 years ago