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Answer.
Date Posted:
6 years ago
Thank you..
Why x can take 0?
My mistake. In that case, there would be no solution to this definite integral. According to this:
http://fooplot.com/#W3sidHlwZSI6MCwiZXEiOiIoKHgrMykoNHgtMikpL3heNCIsImNvbG9yIjoiIzAwMDAwMCJ9LHsidHlwZSI6MTAwMCwid2luZG93IjpbIi02LjUiLCI2LjUiLCItMjAiLCIyMCJdfV0-
The graph has an asymptote for x=0, and has an x-intercept at x=1/2, so a real value can only be determined for a definite integral from 1/2 to 1. From 0 to 1/2, the area under graph (definite integral) cannot be determined.
http://fooplot.com/#W3sidHlwZSI6MCwiZXEiOiIoKHgrMykoNHgtMikpL3heNCIsImNvbG9yIjoiIzAwMDAwMCJ9LHsidHlwZSI6MTAwMCwid2luZG93IjpbIi02LjUiLCI2LjUiLCItMjAiLCIyMCJdfV0-
The graph has an asymptote for x=0, and has an x-intercept at x=1/2, so a real value can only be determined for a definite integral from 1/2 to 1. From 0 to 1/2, the area under graph (definite integral) cannot be determined.
Why x can take 0?