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secondary 4 | Chemistry
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How do I do this?
Take note my method is based on when temperature does not change(because it says decomposed when heated)
Let X be the volume of O2 at the end
Therefore, 2/3 X of O3 decomposed at the start.
Total volume at the end = 20- 2/3 X + X
= 20+ 1/3 X
= 25
Thus X is 15cm^3
At the end you are left with 10cm^3 of O3 and 15cm^3 of O2
Edited: credit to Jerad
There should be 15cm^3 of O2 and 10cm^3 of O3 left in the final reaction mixture instead of the other way round.
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