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Primary 4 | Maths
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Pls help
Date Posted: 6 years ago
Views: 293
O = Mr Ong Money
T = Mr Tan money (at initial)
Z = Mr Tan money (after spent 360)
O = T + 900 (1st equation)
T - 360 = Z (2nd equation)
O = 5Z (3rd)
O ?
Solution:
3rd into 1st
5Z = T + 900
Z = (T + 900)/5 (4th)
4th into 2nd
T - 360 = (T + 900)/5
5(T - 360) = T + 900
5T - 1800 = T + 900
5T - T = 1800 + 900
4T = 2700
T = 2700/4
T = 675
Refer 1st
O = T + 900
T = 675
O = 675 + 900
O = 1575
T = Mr Tan money (at initial)
Z = Mr Tan money (after spent 360)
O = T + 900 (1st equation)
T - 360 = Z (2nd equation)
O = 5Z (3rd)
O ?
Solution:
3rd into 1st
5Z = T + 900
Z = (T + 900)/5 (4th)
4th into 2nd
T - 360 = (T + 900)/5
5(T - 360) = T + 900
5T - 1800 = T + 900
5T - T = 1800 + 900
4T = 2700
T = 2700/4
T = 675
Refer 1st
O = T + 900
T = 675
O = 675 + 900
O = 1575
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Date Posted:
6 years ago
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