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primary 5 | Maths
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Please help me with this question... thank you.
Date Posted: 7 years ago
Views: 600
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First you find CAE which you can find since all the angles in a triangle adds up to 180°.
After identifying CAE = 36°, you know that FAB = FAE + CAB + CAE and that FAB is 90°(angle in a rectangle). Find FAE + CAB by subtracting 90°- 36° =54° (FAB-CAE)
The question states that FAE is twice that of CAB. In ratio form you can write it as FAE : CAB : (FAE+ CAB) = 2 : 1 : 3
To find FAE= 2/3 × 54° (2 units out of the total 3 units)
Hope it helps! (:
After identifying CAE = 36°, you know that FAB = FAE + CAB + CAE and that FAB is 90°(angle in a rectangle). Find FAE + CAB by subtracting 90°- 36° =54° (FAB-CAE)
The question states that FAE is twice that of CAB. In ratio form you can write it as FAE : CAB : (FAE+ CAB) = 2 : 1 : 3
To find FAE= 2/3 × 54° (2 units out of the total 3 units)
Hope it helps! (:
Date Posted:
7 years ago
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