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Primary 4 | Maths
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Hi.. I know i keep asking questions but im really lost here. I do not know how to do the correction..
Date Posted: 6 years ago
Views: 2634
Total mass of biscuits in 3 boxes=500g x 8 =4000g
Let mass of second box be u grams.
Since first box is twice as heavy as second box,
Mass of first box= u x 2= 2u grams
Since third box is 60 grams heavier than second box,
Mass of third box= (2u+60) grams
Total mass of all 3 boxes= u+2u+(2u+60) = 5u+60 grams
(5u+60)g=4000g
5u+60=4000
5u=3940
u=3940 divided by 5=788
The mass of the second box is 788g.
Let mass of second box be u grams.
Since first box is twice as heavy as second box,
Mass of first box= u x 2= 2u grams
Since third box is 60 grams heavier than second box,
Mass of third box= (2u+60) grams
Total mass of all 3 boxes= u+2u+(2u+60) = 5u+60 grams
(5u+60)g=4000g
5u+60=4000
5u=3940
u=3940 divided by 5=788
The mass of the second box is 788g.
Thank you
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Don’t assume the repack 3 boxes are the same. In this question, it states clearly each box requirement. So follow and draw out the model.
Don’t assume the repack 3 boxes are the same. In this question, it states clearly each box requirement. So follow and draw out the model.
Date Posted:
6 years ago
Thank you! (:
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