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International Baccalaureatte | Further Maths HL
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Humzah
Humzah

International Baccalaureatte chevron_right Further Maths HL

Can anyone please help me solve this question, thanks in advance

Date Posted: 1 year ago
Views: 55

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Tham KY
Tham Ky's answer
4627 answers (Tutor Details)
1st
...
Humzah
Humzah
1 year ago
The question says 3sin(2x) for part ii) . you write 2sin(2x)??
Tham KY
Tham KY
1 year ago
Sorry I will redo... For the time being, you may follow the steps, just change the constant accordingly...
Humzah
Humzah
1 year ago
Thank you, i have followed the steps and have found the answer. Thanks
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Tham KY
Tham Ky's answer
4627 answers (Tutor Details)
Correction to part ii)...