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International Baccalaureatte | Maths HL
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Date Posted: 6 years ago
Views: 590
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Did it in a rush, but the method is clear. There might be shorter ways. Always remember solutions to P&C questions must be exhaustive and no overlapping. Cheers.
Date Posted:
6 years ago
Yes, please refer to the other answer given and conisder cases where 4, 5 & 6 are possible when the center digit is 1, 2 & 3. Cheers.
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I did it the longer way, i hope my answer helps. The logic is similar to the other answer. Start by deciding the middle number of your possible answer, and the mumber of digits that your answer has (e.g XY1YX).
Since the digit "1" is selected in our example, and the sum of all digits is 13, therefore X+Y=6.
Continue the process for different middle number (1,3,5,7,9) and number of digits of your answer (3-digits, 5-digits, ... ... 13-digits).
Since the digit "1" is selected in our example, and the sum of all digits is 13, therefore X+Y=6.
Continue the process for different middle number (1,3,5,7,9) and number of digits of your answer (3-digits, 5-digits, ... ... 13-digits).
Date Posted:
6 years ago
Answer should be 62. One case is missing in your solution. :)
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