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secondary 3 | A Maths
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Jeevika Kannan
Jeevika Kannan

secondary 3 chevron_right A Maths

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Date Posted: 6 years ago
Views: 526
Ng Huiying
Ng Huiying
6 years ago
A.12y=9x+69
B.(0,6)
C.15 unit
Joseph Wong
Joseph Wong
6 years ago
First find the grading of the line AC
Gradiant of AC = (9+12)/ (4+8)
=7/4
THEREFORE equation of AC IS
Y=mX+C ;
9=7/4 (4) +C. @pt C (4,9)
C=2 X.=4 , Y=9
Thus, eqn of AC is Y=7/4 X +2

@D, x=0 sub. x=0 into eqation of AC
Y=7/4 (0) +2
Hence Y=2
Point D is (0, 2)
I

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