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Ah you beat me to it haha
The question seemed interesting hence given it a try.. :)
Since the question asked for Max Sn, and there is only one n=20 that makes derivative of Sn w.r.t n equal 0, we assume that n=20 does give the max Sn..
If we want to show that it indeed gives max Sn, we can use the 2nd derivative test.. which i shall post as the next answer.
If we want to show that it indeed gives max Sn, we can use the 2nd derivative test.. which i shall post as the next answer.
thank you!! :)
done
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This continues from the answer above, to show that n=20 indeed give the maximun Sn, if necessary.
Date Posted:
7 years ago