Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
junior college 2 | H2 Maths
One Answer Below
Anyone can contribute an answer, even non-tutors.
Why to find acc at 200ms need draw tangent?
Cant just use the velocity at that time and minus inital 5ms-1?
Date Posted: 6 years ago
Views: 738
See 1 Answer
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Basically, acceleration is a derivative of velocity. You differentiate velocity to get acceleration. Since the graph is a velocity/time graph, draw a tangent at t=200ms (v = 2.9ms-1), find 2 accurate points along the tangent and calculate the acceleration (ms-2) using the gradient formula.
Date Posted:
6 years ago
Thanks! But isnt a=change in v/t?
yes you are right. looking at the axis of the graph it’s v against t right. So when you draw a tangent and find 2 points along the tangent to find the gradient, isn’t (y1-y2)/(x1-x2) the same as (change in v)/(change in t)?
360 Tutoring Program