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secondary 4 | Chemistry
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Date Posted: 7 years ago
Views: 782
1.Ethanoic acid, CH3COOH, is the main compound found in vinega. It has a sour taste and a distinctive pungent smell. Ethanoic acid undergoes many different reactions. When ethanoic acid reacts with a reducing agent, lithium hydride (LiAlH4), ethanol is formed. The chemical equation is shown below.
CH3OOH(aq) - LiAlH4-> CH3CH2OH---Reaction 1
CH3OOH(aq) - LiAlH4-> CH3CH2OH---Reaction 1
When ethanoic acid reacts with magnesium metal, the products obtained are a salt (magnesium ethanoate) and hydrogen gas. The chemical equation is shown below.
2CH3COOH (aq) +Mg (s) - > (CH3COO) 2 Mg (aq) +H2 (g) - - - - Reaction 2
2CH3COOH (aq) +Mg (s) - > (CH3COO) 2 Mg (aq) +H2 (g) - - - - Reaction 2
When ethanoic acid reacts with sodium hydroxide, the products are a salt (Sodium ethanoate) and water. The chemical equation is shown below.
CH3COOH (aq) +NaOH (aq) - > CH3COONa (aq) +H2O (l) - - - Reaction 3
CH3COOH (aq) +NaOH (aq) - > CH3COONa (aq) +H2O (l) - - - Reaction 3
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You can try part (d) yourself.
Hint for part (i), the products are already stated in the question. You just need to balance the equation.
Hint for part (ii), there is no change in the oxidation state of carbon
Hint for part (i), the products are already stated in the question. You just need to balance the equation.
Hint for part (ii), there is no change in the oxidation state of carbon
Date Posted:
7 years ago
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