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junior college 1 | H2 Maths
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Date Posted: 7 years ago
Views: 744
May I know is the answer 9.52 or 33.1?
I got two different methods but different answers! Can't see where is my mistake... Do you have the answer?
I got two different methods but different answers! Can't see where is my mistake... Do you have the answer?
Is 9.52
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done
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Sorry, a bit messy...
Date Posted:
7 years ago
Hmm.. may I ask a question?
Your answer seems to be the volume if you rotate about the y axis . Will the answer not be different from rotating about the line x=-root(10)?
Cause the axis of rotation may be parallel but the solid formed seemed different when I try to imagine it.
Sorry blame on my weak concept when it comes to volume
Your answer seems to be the volume if you rotate about the y axis . Will the answer not be different from rotating about the line x=-root(10)?
Cause the axis of rotation may be parallel but the solid formed seemed different when I try to imagine it.
Sorry blame on my weak concept when it comes to volume
Thank you
Hi Pier Yong, the integration is to find volume if shaded region rotates 360° about x=-√10.
If it was to rotate about y-axis, the volume is just the volume of a cylinder minus the volume of a hemisphere, which gives different answer.
Not sure if I answer your question, coz I don't really understand what you asked! Sorry...
If it was to rotate about y-axis, the volume is just the volume of a cylinder minus the volume of a hemisphere, which gives different answer.
Not sure if I answer your question, coz I don't really understand what you asked! Sorry...
Hi ! The question ask to find to volume rotation about the x-axis, but why didnt you integrate from -square root 10 to 0 ?But you integrate from 0 to square root 10 (which is for rotation about the y-axis).
Question asked for rotation about x=-√10 line, not about x-axis...
Any rotation parallel to y-axis must do integration with respect to y, ie int () dy.
When int () dy is used, limits must be in y.
So the volume is found to be integration from y=0 to y=√10....
Any rotation parallel to y-axis must do integration with respect to y, ie int () dy.
When int () dy is used, limits must be in y.
So the volume is found to be integration from y=0 to y=√10....
Yeah I understand already. Sorry about it
No sorry at all, we share knowledge :)
Okay understood thanks
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