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secondary 2 | Maths
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Xing Yu
Xing Yu

secondary 2 chevron_right Maths

Hi, can some one help me with this question? Thank you

Date Posted: 7 years ago
Views: 371

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A3ium
A3ium's answer
9 answers (A Helpful Person)
1st
16x^(1/3)=2^7-4^3
16x^(1/3)=64
X^(1/3)=64÷16
X^(1/3)=4
X=4^3
=64

^=to the power of
Xing Yu
Xing Yu
7 years ago
Thank you(:
A3ium
A3ium
7 years ago
Np!
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Friendly
Friendly's answer
1 answers (A Helpful Person)
This answers is more clear & explain well?