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secondary 3 | E Maths
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Circle properties
Date Posted: 6 years ago
Views: 597
Angle ABC=90 (right angle in semicricle property)
Angle ACB=180-24 (angle from an external triangle)
So you can find angleOAB already because angle ABC=90degree from the first part. (Angles in a tirangle)
So you can find angleOAB already because angle ABC=90degree from the first part. (Angles in a tirangle)
Angle OBT is also a right angle. The property used here is "radius perpendicular to tangent of the circle"
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Where is D?
Date Posted:
6 years ago
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