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I only stop at y=1-x
dy/dx is just a gradient, you need to form an equation of a straight line for a tangent.
Just that this gradient depends not only on x but also y, make it looks like a straight line eqn.
This special case gives a linear eqn as the solution to dy/dx, makes us confused that was the eqn of the tangent...
Wish you understand my explanation.