Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
junior college 2 | H2 Maths
2 Answers Below
Anyone can contribute an answer, even non-tutors.
Pls help w q1&2 pls!!
Date Posted: 7 years ago
Views: 415
See 2 Answers
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Q1...
Date Posted:
7 years ago
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Q2...
Date Posted:
7 years ago
Why do we have to sub 2 into 1?
I only stop at y=1-x
I only stop at y=1-x
Tangent parallel to x-axis is a perfect horizontal line, y=1-x is not a horizontal line. Must be in the format of y=k where k is a constant.
So this is an unusual case where we have to sub back into the original eqn?
It is unusual if you don't!
dy/dx is just a gradient, you need to form an equation of a straight line for a tangent.
Just that this gradient depends not only on x but also y, make it looks like a straight line eqn.
dy/dx is just a gradient, you need to form an equation of a straight line for a tangent.
Just that this gradient depends not only on x but also y, make it looks like a straight line eqn.
The y=1-x is the result of dy/dx=0, meaning it is the result that cause the gradient to be zero. Not the eqn of the straight line tangent.
Oh okay.. cos Usually when sub dydx =0 will get the eqn of tangent directly, didnt know have to sub back..
Usually after sub dy/dx=0, we found x=constant. This x is the x-coordinate on the curve which has the gradient wanted (in this case, the gradient is zero) then find the corresponding y-coord. Finally we do y-y1=gradient*(x-x1) for the tangent...
This special case gives a linear eqn as the solution to dy/dx, makes us confused that was the eqn of the tangent...
Wish you understand my explanation.
This special case gives a linear eqn as the solution to dy/dx, makes us confused that was the eqn of the tangent...
Wish you understand my explanation.
Ohh alright thank you!
360 Tutoring Program