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primary 6 | Maths
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Date Posted: 6 years ago
Views: 529
21 correct, 9 wrong
Simplest approach: Since she has 54 marks, she must have at least 18 correct answers, trial and error from 18 correct-12wrong and so on, u can get this answer
Simplest approach: Since she has 54 marks, she must have at least 18 correct answers, trial and error from 18 correct-12wrong and so on, u can get this answer
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done
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I solved this using algebra method, not sure whether you understand or not
Date Posted:
6 years ago
Thank you
done
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A standard kind of question which does not require trial and error. Assumption method: assume are 30 questions are correct--> should get 90 marks but only 54 marks. The difference (36marks) is due to the number of questions answered wrongly. With every question answered wrongly, this person gets 4 less marks (compared to 1 question answered correctly). Divide by 4, that is 9 questions answered wrongly.
Date Posted:
6 years ago
Thank you so much!
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