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secondary 3 | A Maths
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Date Posted: 3 weeks ago
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y = mx + c and x² + y² = 4
x² + (mx + c)² = 4
(1 + m²)x² +2mcx + c² - 4 = 0
Since the line is tangent to the curve
-> Discriminant = 0
-> 4m²c² - 4(1 + m²)( c² - 4) = 0
-> 4m² = c² - 4
when c = 2, m = 0
Hence y = 2 is a tangent to the curve
x² + (mx + c)² = 4
(1 + m²)x² +2mcx + c² - 4 = 0
Since the line is tangent to the curve
-> Discriminant = 0
-> 4m²c² - 4(1 + m²)( c² - 4) = 0
-> 4m² = c² - 4
when c = 2, m = 0
Hence y = 2 is a tangent to the curve
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