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junior college 2 | H2 Maths
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Why cant Br2 in CCl4 be used in this case?
By using a polar solvent e.g. water, a stronger dipole is induced in Br-Br, resulting in more/stronger electrophile Br+, which is much more susceptible to attack by the benzene ring. Hence a white ppt of tribromophenylamine can be obtained.
In the case of CCl4, because it is non-polar, the effects of electrophilic substitution are less pronounced, resulting in only mono-substitution (instead of tri), where no white ppt is observed.