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secondary 4 | A Maths
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Please help me with this Differentiation Question (d). Somewhere wrong with my working, can’t get the correct answer. Thank you.
Date Posted: 1 week ago
Views: 84
Looks good as a start! We proceed to factor common terms as far as possible ie (1 - 2x)³.
y = (x² - 3x + 4) (1 - 2x)⁴
dy/dx
= (x² - 3x + 4) (-8) (1 - 2x)³ + (2x - 3) (1 - 2x)⁴
(We factor out the common (1 - 2x)³)
= (1 - 2x)³ [-8 (x² - 3x + 4) + (2x - 3) (1 - 2x)¹]
= (1 - 2x)³ [-8x² + 24x - 32 + 2x - 4x² - 3 + 6x]
= (1 - 2x)³ [-12x² + 32x - 35]
dy/dx
= (x² - 3x + 4) (-8) (1 - 2x)³ + (2x - 3) (1 - 2x)⁴
(We factor out the common (1 - 2x)³)
= (1 - 2x)³ [-8 (x² - 3x + 4) + (2x - 3) (1 - 2x)¹]
= (1 - 2x)³ [-8x² + 24x - 32 + 2x - 4x² - 3 + 6x]
= (1 - 2x)³ [-12x² + 32x - 35]
A similar factorisation strategy is required to achieve the given solution for part e of your worksheet.
Mr. Eric Nicholas, thank you, and appreciate it. I understand now.
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done
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Pls post a clearer pic, in future.
Author of several O-level Science guide books (my profile pic). My forte is tutoring O-level sciences (Chemistry, Physics, Biology). Telegram Messenger: @ChillXsg Note that only my tuition students have the privilege to direct message questions, to clarify.
Author of several O-level Science guide books (my profile pic). My forte is tutoring O-level sciences (Chemistry, Physics, Biology). Telegram Messenger: @ChillXsg Note that only my tuition students have the privilege to direct message questions, to clarify.
Date Posted:
1 week ago
Mr. Arnold Tan, thank you, and appreciate it. Understand now.
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