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primary 5 | Maths
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What is the solution to question C and why the solution?
Date Posted: 1 month ago
Views: 65
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done
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Hope this helps
Date Posted:
1 month ago
Hi AC, thanks for the solution but may i know divide by 2?
We paired the every 2 number to 101.
Example:
1+100 = 101
2+99 = 101
3+98 = 101
....
.
.
.
50+51 = 101
Therefore, total have 50 pairs of 101
50x101 = 5050
Example:
1+100 = 101
2+99 = 101
3+98 = 101
....
.
.
.
50+51 = 101
Therefore, total have 50 pairs of 101
50x101 = 5050
done
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clear
{{ downvoteCount * -1 }} Downvotes
Explanation for your reference.
Date Posted:
1 month ago
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