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primary 6 | Maths
| Geometry
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Can help for part b for the formula of grey circles? Thank u
Date Posted: 6 months ago
Views: 117
Alternative for part c)
Every jump of 2 figures results in an increase of 1 grey circle.
From figure 1 to figure 425,
425 - 1 = 424
There is a increase of 424 figures.
424 ÷ 2 = 212
There were 212 jumps. So grey circles increased by 212
2 + 212 = 214
There are 214 circles in figure 425.
From here it is easy to solve.
Every jump of 2 figures results in an increase of 1 grey circle.
From figure 1 to figure 425,
425 - 1 = 424
There is a increase of 424 figures.
424 ÷ 2 = 212
There were 212 jumps. So grey circles increased by 212
2 + 212 = 214
There are 214 circles in figure 425.
From here it is easy to solve.
A more direct way:
Every jump of 2 figures results in an increase of 5 white circles.
From figure 1 to figure 425,
425 - 1 = 424
There is a increase of 424 figures.
424 ÷ 2 = 212
There were 212 jumps.
212 x 5 = 1060
Number of white circles increased by 1060.
4 + 1060 = 1064
There are 1064 circles in Figure 425.
Percentage that were white circles
= 100% x 1064/1278
≈ 83.255%
= 83.3% (to 1 decimal place)
Every jump of 2 figures results in an increase of 5 white circles.
From figure 1 to figure 425,
425 - 1 = 424
There is a increase of 424 figures.
424 ÷ 2 = 212
There were 212 jumps.
212 x 5 = 1060
Number of white circles increased by 1060.
4 + 1060 = 1064
There are 1064 circles in Figure 425.
Percentage that were white circles
= 100% x 1064/1278
≈ 83.255%
= 83.3% (to 1 decimal place)
See 1 Answer
Thank u!
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