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Question
secondary 3 | A Maths
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Date Posted: 1 month ago
Views: 46
2x² - 4x + 7
= 2(x² - 2x) + 7
= 2(x - 2x(1) + 1² - 1²) + 7
= 2(x - 2x(1) + 1²) - 2 + 7
= 2(x - 1)² + 5
= 2(x² - 2x) + 7
= 2(x - 2x(1) + 1² - 1²) + 7
= 2(x - 2x(1) + 1²) - 2 + 7
= 2(x - 1)² + 5
Alternatively,
2x² - 4x + 7
= 2(x² - 2x + 3.5)
= 2( (x - 2/2)² - (2/2)² + 3.5 )
= 2( (x - 1)² - 1 + 3.5 )
= 2( (x - 1)² + 2.5 )
= 2(x - 1)² + 5
2x² - 4x + 7
= 2(x² - 2x + 3.5)
= 2( (x - 2/2)² - (2/2)² + 3.5 )
= 2( (x - 1)² - 1 + 3.5 )
= 2( (x - 1)² + 2.5 )
= 2(x - 1)² + 5
See 1 Answer
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Date Posted:
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