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secondary 2 | Maths
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Jane
Jane

secondary 2 chevron_right Maths chevron_right Singapore

Please help with explanation on how to to link 10x^2 = 23x -12 to 10(y-3)^2 = 23y - 81

Date Posted: 1 month ago
Views: 63
Hello
Hello
1 month ago
cant you just expand (y-3)^2? then solve for y?

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Pyae Phyo Kyaw
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Jane
Jane
1 month ago
The answer for 2(i) is x= 1.5 or 0.8
Jane
Jane
1 month ago
Its 23x not 2x
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Hello
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