Please help with explanation on how to to link 10x^2 = 23x -12 to 10(y-3)^2 = 23

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secondary 2 | Maths
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secondary 2 Maths Singapore

Please help with explanation on how to to link 10x^2 = 23x -12 to 10(y-3)^2 = 23y - 81

Date Posted: 3 months ago

Hello

3 months ago

cant you just expand (y-3)^2? then solve for y?

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Date Posted: 3 months ago

Jane

3 months ago

The answer for 2(i) is x= 1.5 or 0.8

Jane

3 months ago

Its 23x not 2x

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Date Posted: 3 months ago