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Secondary 1 | Maths
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pls help
Date Posted: 3 months ago
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Area of the cross-section of the wooden toy
= area of triangle + area of rectangle - area of circle
= 1/2(50)(60-40) + (40)(50) - π(30/2)²
= 500 + 2000 - 706.858347058
= 1793.14 cm² (2d.p.)
= area of triangle + area of rectangle - area of circle
= 1/2(50)(60-40) + (40)(50) - π(30/2)²
= 500 + 2000 - 706.858347058
= 1793.14 cm² (2d.p.)
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