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junior college 2 | H2 Maths
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pls help
Date Posted: 7 months ago
Views: 153
Possible selections = no repeats + 1 repeat + 2 repeats = 5C3 + 2C1 × 4C1 + 1C1
P(1 repeat) = 2C1 × 4C1 /(5C3 + 2C1 × 4C1 + 1C1)
P(1 repeat) = 2C1 × 4C1 /(5C3 + 2C1 × 4C1 + 1C1)
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If you like programming, try writing code to simulate this and find all cases.
Date Posted:
7 months ago
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