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Question
junior college 2 | H2 Maths
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pls help
Date Posted: 7 months ago
Views: 167
a) (3/10)² × 2/10 × 5/10 × 4!/2!
bi) 5/10 × 4/9 × 3/8 × 2/7 × 4!/2!
bii) P(repeated green) + P(repeated blue) + P(repeated white)
= (5/10 × 4/9 × 3/8 × 2/7 + 3/10 × 2/9 × 5/8 × 2/7 + 2/10 × 1/9 × 5/8 × 3/7) × 4!/2!
Note that 4!/2! represents the permutation for 4 items of which 2 are identical.
bi) 5/10 × 4/9 × 3/8 × 2/7 × 4!/2!
bii) P(repeated green) + P(repeated blue) + P(repeated white)
= (5/10 × 4/9 × 3/8 × 2/7 + 3/10 × 2/9 × 5/8 × 2/7 + 2/10 × 1/9 × 5/8 × 3/7) × 4!/2!
Note that 4!/2! represents the permutation for 4 items of which 2 are identical.
See 1 Answer
i believe these answers for (a) & (b)(ii) are not correct.
for (a), the question states that the 4 balls are taken WITH REPLACEMENT. this means that number of balls remains the same. the answer posted on left, is assuming the case of 4 balls taken without replacement.
(b)(ii) answer is incorrect due to error carried forward from (a).
answers given by EPQP in comments in main section should be the correct answers.
for (a), the question states that the 4 balls are taken WITH REPLACEMENT. this means that number of balls remains the same. the answer posted on left, is assuming the case of 4 balls taken without replacement.
(b)(ii) answer is incorrect due to error carried forward from (a).
answers given by EPQP in comments in main section should be the correct answers.
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